Next $$$q$$$ lines contain five integers $$$x$$$, $$$y$$$, $$$a$$$, $$$b$$$, and $$$k$$$ each ($$$1 \le x,y,a,b \le n$$$, $$$x \ne y$$$, $$$1 \le k \le 10^9$$$) the integers explained in the description. Using Segment Tree Range Minimum Query (C++) - LeetCode The fourth query is $$$[4, 8, 2]$$$. 1 + Div. Auto comment: topic has been updated by rengokudied (previous revision, new revision, compare). When we "delete" an edge, we just update its value to be 1. This year, the sets of SEERC and OpenCup are a bit different: OpenCup won't include a few easier problems from SEERC and will additionally include several harder problems. Don't get it wrong: if we iterate over a path just, for example, by going from both endpoints towards the root, it gets tl (even with pragmas): submission. The root of the tree is a vertex number $$$1$$$. Vertices are numbered from $$$1$$$ to $$$n$$$. Then he chooses some vertex $$$r$$$. I created a video tutorial explaining the problem. It is a great problem to learn a variation of traditional segment trees. Range Minimum Query(RMQ) - Topcoder In this problem you need to answer to m queries. Each query is finding number of weights in level (k + lev [node]) with DFS in-time in the range [in [node], out [node]]. The problem statement has recently been changed. The problem Ball Machine from BOI2013 can be solved using a similar idea. A tree with $$$n$$$ vertices is an undirected connected graph with $$$n-1$$$ edges. Problem link: Here is a link to my solution: The complexity is around O(q*log(n)) for all the print queries. I'm not into HLD especially, but look a modern memory model has multiple cache levels: registers (in the core), L1, L2, L3 and RAM itself. $$$2$$$ $$$v$$$ ($$$1 \leq v \leq n$$$), representing a second-type operation. We can then apply the above idea and solve this problem in $$$O(M \log N)$$$ time. 2D Range Queries USACO Guide Segment Tree Query - Codeforces It is supported only ICPC mode for virtual contests. 2), Teams going to ICPC WF 2023 (Egypt 2023, 2nd final) WIP List, Atcoder problem statement of F Cans and Openers, Invitation to SmallForces Monthly Contest #3, How do I get blue in codeforces in 1 month, Educational Codeforces Round 152 Editorial, How to solve http://www.spoj.com/problems/SUMMUL/, Educational Codeforces Round 144 Editorial, UNIQUE VISION Programming Contest 2023 Summer(AtCoder Beginner Contest 312) Announcement. Minimize diameter of tree by applying almost k.operations. -is-this-fft- [Tutorial] The DFS tree and its applications: how I found out I really didn't understand bridges . The next $$$m$$$ lines describe queries. I think it's about dsu on tree https://codeforces.com/blog/entry/44351. Contribute to kantuni/Codeforces development by creating an account on GitHub. The answer to query vj, kj is the number of such colors of vertices x, that the subtree of vertex vj contains at least kj vertices of color x. On the other hand, one can use heavy-light decomposition (this particular implementation is not necessary, I suppose, but it's still very nice) first (that is, sort every vertex' children by their subtree sizes), then rearrange vertices by their dfs in-order, and voil, every path is now a union of about $$$\sim\log{n}$$$ consecutive segments. CSES - Path Queries II Notice how if we make the edge $$$(u, v)$$$ activated, then the new amount of information on all nodes in the merged component is $$$a_u + a_v - c_v$$$. We can combine the 2 ideas above to work on trees if we want to increase the value of node $$$u$$$ by $$$X$$$, we increase $$$b[tin_u]$$$ by $$$X$$$ and decrease $$$b[tout_u + 1]$$$ by $$$X$$$. Check whether $$$l_u$$$ is an ancestor of $$$v$$$ and whether $$$l_v$$$ is an ancestor of $$$u$$$. If $$$r = 4$$$, the values of vertices $$$1$$$, $$$2$$$, $$$3$$$ and $$$5$$$ get increased. Next m lines contain the queries. Problem link: Codeforces. Can anybody look at my code of problem 1: Infoarena Disconnect and tell my why this code gives TLE for the last 6 test cases? Tutorial Suppose that you want to support the following operations on a tree: Update all nodes along the path from node x x to node y y. Firstly, root the tree arbitrarily. Summer 2018, Xi Lin Contest 4: HDU. By cache miss I just meant the total size of graph traversed by DFS. On the other hand, it's easy to get ac with an $$$O(nq)$$$ solution. Otherwise, print "NO". E. 1-Trees and Queries time limit per test 4 seconds memory limit per test 512 megabytes input standard input output standard output Gildong was hiking a mountain, walking by millions of trees. Codeforces. TryOmar Code Collection Covering Bubble Sort, Binary Search, Lower Bound, . The first line contains two integers n and m (2n105;1m105). OK I got AC :<. which data structures need problems same as above? Process $$$M$$$ of the following queries online: $$$N \leq 10^5$$$ and $$$M \leq 5 \cdot 10^5$$$. It is supported only ICPC mode for virtual contests. Can you please explain why there are only O(nlogn) caches miss ? It is supported only ICPC mode for virtual contests. The Fox and the Complete Tree Traversal (2400) F. Misha and Apples (2800) 15. dolphingarlic or someone: What exactly is being done here (in the solution for Problem 1)? - (n!/(k+1), Competitive Programming Roadmap (target: [gray, blue]), Codeforces Round 887 (Div 1, Div 2) Tutorial. We can then use LCA and the principle of inclusion-exclusion to find the sum of nodes/edges on the path between nodes $$$u$$$ and $$$v$$$. f 0[i][j]: the j-MSS in [0, i]. Minimize diameter of tree by applying almost k.operations. I think the collected path information will be small enough to fit in L2 or L3, but Im not an expert on this topic. EDIT: didn't read the problem statement carefully enough, my bad. Programming competitions and contests, programming community. The idea of that problem is to count the amount each edge contributes to the answer. Then when we want to find the value of the element at $$$C$$$, we simply query the sum of $$$BIT[i]$$$ for each $$$i$$$ from 0 to $$$C$$$. Let the time we enter node $$$i$$$ be $$$tin_i$$$ and the time we exit it be $$$tout_i$$$. CodeForces 877E, Tree Queries and Data Structures - YouTube Recent codechef long challenge had a task about queries on paths inside a tree: short, given a tree, each vertex contains a linear function, and given q queries of types "add given linear f to all vertices of the path between u and v " and "calculate maximum of f ( z) where z is given and f is a function in any of vertices on the path between gi. Tree Queries (Easy Version) (2200) D2. The amount of information stored on $$$i$$$ is thus $$$a_{root[i]}$$$. Virtual contest is a way to take part in past contest, as close as possible to participation on time. CodeForces 825G "Tree Queries" (select roots to build trees) Number of elements greater than K in the range L to R using Fenwick If $$$r = 4$$$, the values of vertices $$$1$$$ and $$$3$$$ get increased. Instead of solving it by himself, he's going to test you by providing queries on 1-trees. Codeforces/E_Tree_Queries.cpp at master - GitHub The add function will simply add the value of the position and subsequently update the answer variable. . But if you are looking for tree query related problems, you can try QTREE , QTREE2 , QTREE3 , QTREE4 , QTREE5 , QTREE6. Recursive: long long query(int l, int r) { if(l > r)return 0; int node = N + l - 1; int K = min(logs[node & -node], logs[r - l + 1]); return (query(l + (1 << K), r) + seg[node >> K]); } Iterative: Introduction Notations Range Minimum Query (RMQ) Trivial algorithms for RMQ A < O(N), O(sqrt(N)) > solution Sparse Table (ST) algorithm Segment Trees Lowest Common Ancestor(LCA) A<O(N), O(sqrt(N))> solution Another easy solution in <O(N logN, O(logN)> Reduction from LCA to RMQ From RMQ to LCA An <O(N), O(1)> algorithm for the . This is also particularly useful when optimizing a tree dp. It is guaranteed that the edge between $$$x$$$ and $$$y$$$ does not exist in the original tree. Note: Whenever I talk about edge $$$(u, v)$$$ in this post, I assume that $$$u$$$ is the parent of $$$v$$$. I can think of a solution that uses HLD + Fenwick, but I'm curious to see if there is a solution that uses the technique in the post. For other people like me who didn't get the idea behind this when skimming through the post, the main goal of doing HLD is to have the vertices from a path continuous in memory, as opposed to being all over the place like when you're iterating over parent links. Description Let there be a tree G of n vertices, with an arbitrary root. So, basic enough and cache-friendly operations are fast enough in practice. However, say we can express all path passing centroid, as a combination of two path from centroid. . Let the root of $$$i$$$'s component be $$$root[i]$$$. A tree is a connected undirected graph with $$$n-1$$$ edges. And for the updates it is logn for each value to be updated.I don't think we can do better than that.This however gives a TLE verdict.Any suggestions? It is guaranteed that the sum of $$$k_i$$$ does not exceed $$$2 \cdot 10^5$$$ ($$$\sum\limits_{i=1}^{m} k_i \le 2 \cdot 10^5$$$). Increase the value of $$$a_i$$$ by $$$X$$$, Find the sum of $$$a_i$$$ on the path from $$$u$$$ to $$$v$$$ for 2 nodes $$$u$$$ and $$$v$$$. Subordinates This can be solved using basic DP approach in linear time. You can print each letter in any case (upper or lower). - (n!/(k+1), Competitive Programming Roadmap (target: [gray, blue]), Codeforces Round 887 (Div 1, Div 2) Tutorial. Never use someone else's code, read the tutorials or communicate with other person during a virtual contest. After all these events, you want to know how many unique pieces of information are stored in each node. Problem - 375D - Codeforces The $$$i$$$-th line describes the $$$i$$$-th query and starts with the integer $$$k_i$$$ ($$$1 \le k_i \le n$$$) the number of vertices in the current query. For the second query, where $$$v = 2$$$ and $$$d = 2$$$: Hence, the expected values of all vertices after this query are ($$$2.2, 2.4, 2, 2, 2$$$). That's a first time I see somebody have analysis on number of a cache misses better than "well, we go through all the data in right order so it should be fast(er)" but the interesting part: if I comment out sort part in the solution it still gets AC in 1.67 (and probably may be even a bit more faster if I delete all the code that actually calculates sizes which I am lazy to perform) so this time "by sorting we make paths closer in memory" analysis seems to be enough. 1569C - Jury Meeting: Not able to calculate n! The CPU loads inside L3 a bigger block, inside L2 there is a smaller subblock of a block, and so on. LCA in a tree using Binary Lifting Technique - GeeksforGeeks Segment Tree - Algorithms for Competitive Programming I hope you've learned something from this tutorial. The original problem requires you to find the sum of edges on a line graph, which you can do with a line sweep. Optimizations like these should be thoroughly benchmarked before making any claims, let alone going into production. In your code, you have lots of hot loops iterating from 1 to 16 or similar. https://pastebin.com/X6ASEEvg, Also in case anyone is curious, here is my HLD + BIT solution (which also got AC): https://pastebin.com/duZ3cjPR. Grid Reconstruction (1000) C. Ian and Array Sorting (1300) D. Sum Graph (2000) E. Between . The picture corresponding to the example: The first query is $$$[3, 8, 9, 10]$$$. . Programming competitions and contests, programming community . Tree This problem can also be solved using segment trees with range minimum queries as well. Also maintain a list of nodes for each level in the order in which they appear during the DFS. Initially, Hanh sets the value of every vertex to 0. There will be a Grand Prix of Southeastern Europe based on these problems this Sunday, November 28, 08:00 UTC. And it works ~3 sec on CF on the worst case. The third query is $$$[2, 1, 5]$$$. My solution used this technique with $$$O(\sqrt{n})$$$ for update and $$$O(\sqrt{n}$$$ $$$log$$$ $$$n)$$$ to get answer. I'm quite sure it can be done with heavy-light decomposition but I couldn't get a solution! If $$$r = 1$$$, the values of all vertices get increased. Heavy-light decomposition - Algorithms for Competitive Programming But if you are looking for tree query related problems, you can try QTREE , QTREE2 , QTREE3 , QTREE4 , QTREE5 , QTREE6 Reply +3 You can find the definition of a rooted tree by the following link: http://en.wikipedia.org/wiki/Tree_ (graph_theory). One more problem for this trick: http://codeforces.com/contest/925/problem/E (1.1s AC with 5s TL), The only programming contests Web 2.0 platform, http://codeforces.com/contest/925/problem/E, Editorial of Codeforces Round 889 (Div. Help needed in Subtree Queries CSES - Codeforces CodeForces 877E is an interesting problem that requires queries and updates on subtrees of a tree. Wiki E-maxx (Russian) Reply Bidhan +3 I didn't understand clearly. 1569C - Jury Meeting: Not able to calculate n! How to do fractional cascading on an iterative segment tree? This works because if $$$C$$$ isn't inside the range of an update, the 2 values we update "cancel out" in the query. Unfortunately its my favorite trick too :) Similar thing also goes to centroid decomposition as well. Problem - 1328e - Codeforces Here is the link to the OpenCup. who have weight nodes or edges ? Seems like a different kind of problem (since you're updating paths rather than points). stdfloat Groups contain OI problems on Codeforces . A tree is a connected undirected graph with n 1 n 1 edges. Delete the edge $$$(u, v)$$$ from the path. The answer is "YES" as you can choose the path to the vertex $$$u=9$$$ so vertices $$$2$$$ and $$$4$$$ both have distance $$$1$$$ to the vertex $$$1$$$ which belongs to this path and the vertex $$$8$$$ has distance $$$1$$$ to the vertex $$$7$$$ which belongs to this path. 2), Teams going to ICPC WF 2023 (Egypt 2023, 2nd final) WIP List, Atcoder problem statement of F Cans and Openers, Invitation to SmallForces Monthly Contest #3, How do I get blue in codeforces in 1 month, Educational Codeforces Round 152 Editorial, How to solve http://www.spoj.com/problems/SUMMUL/, Educational Codeforces Round 144 Editorial, UNIQUE VISION Programming Contest 2023 Summer(AtCoder Beginner Contest 312) Announcement. I've come across several problems that require you to be able to efficiently find the sum of some values on a path from $$$A$$$ to $$$B$$$ in a tree. Dynamic Programming on Tree (Complete Series) - CodeChef Discuss I cant seem to understand the logical error i am doing . July is already the warmest month on record, scientists calculate | AP News GitHub, DP on Trees: Appleman and Tree | Codeforces | Rated 2000 - YouTube, Binary Tree Cameras | Leetcode | DP on Trees - YouTube, Binary lifting: Dynamic Programming on Trees - YouTube, Dynamic Programming on Trees - Codeforces. LCA in a tree using Binary Lifting Technique A Amol_Pratap Read Discuss Courses Practice Given a binary tree, the task is to find the Lowest Common Ancestor of the given two nodes in the tree. $$$root_u$$$ is the lowest ancestor of $$$u$$$ such that the path from $$$u$$$ to $$$root_u$$$ contains no deactivated edges. Excuse me, I didn't understand why your solution is faster than $$$O(nm)$$$. pratikshaw CSES MONSTERS . This solution runs in $$$O(M \log^2 N)$$$ time. There are $$$M$$$ events. Input The first input line contains two integers n and q: the number of nodes and queries. Then vertices $$$[3, 9, 10]$$$ belong to the path from $$$1$$$ to $$$10$$$ and the vertex $$$8$$$ has distance $$$1$$$ to the vertex $$$7$$$ which also belongs to this path. With the sizes swapped, you are accessing the bytes in sequence (at least in a forward loop, backwards pre-fetching depends on the smartness of the compiler). Using binary lifting, we can find the root of any component in $$$O(\log^2 N)$$$ time. Codeforces. If you just want to solve some problem from a contest, a virtual contest is not for you - solve this problem in the archive. I am surprised, that it makes such a difference. The only programming contests Web 2.0 platform, Editorial of Codeforces Round 889 (Div. CF 800. You have a rooted tree consisting of n vertices. bicsi - Codeforces Is v necessary? 1569C - Jury Meeting: Not able to calculate n! Notice how there is a path from $$$u$$$ to $$$v$$$ if and only if the sum of edges on the path between $$$u$$$ and $$$v$$$ is 0. Heavy light decomposition (with Segment tree) problem for beginners : http://acm.timus.ru/problem.aspx?space=1&num=1553 If you need the code, you can see my code: https://sites.google.com/site/kc97ble/container/heavylight-cpp, The only programming contests Web 2.0 platform, Editorial of Codeforces Round 889 (Div. Am I mistaken, as the approaches feels different to me as Mo on trees relies on modified dfs traversal, the other uses the normal preorder array, the MO one is more generalized also. Help needed in Subtree Queries CSES - Codeforces The answer to query vj,kj is the number of such colors of vertices x, that the subtree of vertex vj contains at least kj vertices of color x. It is guaranteed that these $$$n - 1$$$ edges form a tree. If $$$r = 2$$$, the values of vertices $$$1$$$ and $$$3$$$ get increased. Your task is to say if there is a path from the root to some vertex $$$u$$$ such that each of the given $$$k$$$ vertices is either belongs to this path or has the distance $$$1$$$ to some vertex of this path. For example, if we wanted to add $$$X$$$ to the subtree of $$$a_i$$$ in $$$O(\log N)$$$ time? It is guaranteed that all vertices in a single query are distinct. 2), Teams going to ICPC WF 2023 (Egypt 2023, 2nd final) WIP List, Atcoder problem statement of F Cans and Openers, Invitation to SmallForces Monthly Contest #3, How do I get blue in codeforces in 1 month, Educational Codeforces Round 152 Editorial, How to solve http://www.spoj.com/problems/SUMMUL/, Educational Codeforces Round 144 Editorial, UNIQUE VISION Programming Contest 2023 Summer(AtCoder Beginner Contest 312) Announcement. Problem - 1304E - Codeforces How to do fractional cascading on an iterative segment tree. The first line of the input contains two integers $$$n$$$ and $$$m$$$ ($$$2 \le n \le 2 \cdot 10^5$$$, $$$1 \le m \le 2 \cdot 10^5$$$) the number of vertices in the tree and the number of queries. Help needed in Subtree Queries CSES By rengokudied , history , 44 hours ago , I have been trying to flatten the tree using euler tour and then making a segment tree on the value array for point update and range query . You can do a DFS, maintaining in time and out time. The only programming contests Web 2.0 platform. Nice Tutorial.Hope I have learnt something new and interesting. If you just want to solve some problem from a contest, a virtual contest is not for you - solve this problem in the archive. But how do we find the root of a component? Let the value of each edge in the tree initially be 0. It is guaranteed that the given edges form a tree. Yeah. 1-Trees and Queries CodeForces-1304E 1-Trees and Queries Codeforces 1304E 1-Trees and Queries (distance on trees + thinking) (translation direction) CodeForces-1304 E 1-Trees and queries Method quot hdu 1408 acdearm &quot;Money, Money, Money&quot; Codeforces 1467E Distinctive Roots in a Tree Codeforces 1304E. The only programming contests Web 2.0 platform, A path can contain the same vertices and same edges multiple times, $$$1$$$-st query: $$$1$$$ $$$3$$$ $$$2$$$, $$$2$$$-nd query: $$$1$$$ $$$2$$$ $$$3$$$, $$$4$$$-th query: $$$3$$$ $$$4$$$ $$$2$$$ $$$3$$$ $$$4$$$ $$$2$$$ $$$3$$$ $$$4$$$ $$$2$$$ $$$3$$$. If $$$r = 2$$$, the values of all vertices get increased. If you only update tin[i] instead of both tin[i] and tout[i], you can get the subtree sum by querying the range [tin[i], tout[i]]. PDF Codeforces #172 Tutorial It's a generalization of JOI 2015 Railroad. As for HLD, in each path from a vertex to a vertex, we have here a O(logn) different subpaths, and each subpath is a consequtive segment in memory. [Tutorial] Path sum queries on a tree using a Fenwick tree. If $$$r = 3$$$, the values of vertices $$$2$$$, $$$4$$$ and $$$5$$$ get increased. Initially, Hanh sets the value of every vertex to $$$0$$$. Find the sum, maximum, minimum (or any other operation that satisfies the associative property) along the path from node x x to node y y. Never use someone else's code, read the tutorials or communicate with other person during a virtual contest. Next line contains an integer $$$q$$$ ($$$1 \le q \le 10^5$$$), the number of queries Gildong wants to ask. Each vertex of the tree has some color. The image below describes the tree (circles and solid lines) and the added edges for each query (dotted lines). snehitha12 Query regarding my rating in past few contests . I tried to cut off solutions with bad time complexity (what is hard when main complexity is $$$O(n\sqrt{n}$$$ $$$log n)$$$), but I didn't expect this. September 26, 2019 10:34. We can then use PIE to query subrectangles. Then when we want to find the sum of nodes on the path between node $$$v$$$ and the root, we simply query the sum of $$$b[i]$$$ for each $$$i$$$ from 0 to $$$tin_v$$$. Always try to remember which those are. For example if we are asked to find range sum queries then we use a simple integer as data structure, which is $0$ at the beginning. Each query is described by two integers vj,kj. Next $$$n-1$$$ lines contain two integers $$$u$$$ and $$$v$$$ ($$$1 \le u,v \le n$$$, $$$u \ne v$$$) each, which means there is an edge between vertex $$$u$$$ and $$$v$$$. This means we can simply set $$$a_v$$$ and $$$c_v$$$ to equal $$$a_{root[u]}$$$ when that happens (we don't care what $$$a_v$$$ and $$$c_v$$$ were before this). All nodes in the merged component will contain all the information stored on the other nodes in the component. Minimize diameter of tree by applying almost k.operations. The "further" our target variable from the core, the slower (waaaaaay too slower) it is to obtain it. The next n-1 lines contain the edges of the tree. During obtaining the variable, cache levels load into itself not only the variable, but also its memory block, where it belongs. If you're familiar with range updates and point queries with Fenwick trees, you'll know that if we want to increase the range $$$[A, B]$$$ by $$$X$$$ in an array/Fenwick tree $$$BIT$$$, then we increase $$$BIT[A]$$$ by $$$X$$$ and decrease $$$BIT[B + 1]$$$ by $$$X$$$. SD Segment Tree Variation, A Shorter And More Efficient - Codeforces If $$$r = 5$$$, the values of vertices $$$1$$$ and $$$3$$$ get increased. "JOI 2015 Railroad but on a general tree instead of a line" Is this a generalization of a particular problem? I tried the following instead (as this forces +1 to be contributed to the LCA): And query the max over the sums in [tin[u], tout[u] 1], I was able to get AC! - (n!/(k+1), Competitive Programming Roadmap (target: [gray, blue]), Codeforces Round 887 (Div 1, Div 2) Tutorial. // qs --> query start index, qe --> query end index int RMQ (node, qs, qe) { if range of node is within qs and qe return value in node else if range of node is completely outside qs and qe return INFINITE else return min ( RMQ (node's left child, qs, qe), RMQ (node's right child, qs, qe) ) } Help needed in Subtree Queries CSES - Codeforces Contests rengokudied's blog Help needed in Subtree Queries CSES By rengokudied , history , 4 minutes ago , I have been trying to flatten the tree using euler tour and then making a segment tree on the value array for point update and range query . Ideone. Your task is to process following types of queries: change the value of node s to x find the maximum value on the path between nodes a and b. NotImplemented +3 Heavy-Light Decomposition. The answer is "YES" as you can choose the path to the vertex $$$u=2$$$. All queries are independent of each other; i.e. When the edge $$$(u, v)$$$ becomes activated, $$$u$$$'s component and $$$v$$$'s component merge and "sync up". He loves growing trees and doing experiments on his own garden. CFTracker Path max queries on a tree in O(1) - Codeforces List of All Petrozavodsk Contests - Codeforces Heavy-Light Decomposition USACO Guide Then $$$k_i$$$ integers follow: $$$v_i[1], v_i[2], \dots, v_i[k_i]$$$ ($$$1 \le v_i[j] \le n$$$), where $$$v_i[j]$$$ is the $$$j$$$-th vertex of the $$$i$$$-th query. Pay attention Please someone guide. Inspired by them, he suddenly came up with an interesting idea for trees in data structures: What if we add another edge in a tree? The essence of this tree decomposition is to split the tree into several paths so that we can reach the root vertex from any v by traversing at most log n paths. Here, for a given range , the segment tree should return the index of the minimum value of that range (not the minimum value itself but the index of that value). This means you're asked to determine if there exists a path from vertex $$$a$$$ to $$$b$$$ that contains exactly $$$k$$$ edges after adding a bidirectional edge between vertices $$$x$$$ and $$$y$$$. Minimize diameter of tree by applying almost k.operations. In other words, output such an integer $$$x$$$ that $$$0 \le x < M$$$ and $$$x \cdot q \equiv p \pmod{M}$$$. GitHub Distance in Tree This problem also uses the rerooting technique. Since Gildong was bored of solving too many tree problems, he wanted to see if similar techniques in trees can be used in 1-trees as well. "It's way beyond everything we see," Haustein . In this blog post, I will describe a way to solve these types of problems using just a DFS, a Fenwick tree, and LCA (as well as a way to solve JOIOC 2013 Synchronization this way). Can you please briefly explain how it would work? And for the updates it is logn for each value to be updated.I dont think we can do better than that.This however gives a TLE verdict.Any suggestions?
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